5(x+1)=9[x-(3-x)]

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Solution for 5(x+1)=9[x-(3-x)] equation:


Simplifying
5(x + 1) = 9[x + -1(3 + -1x)]

Reorder the terms:
5(1 + x) = 9[x + -1(3 + -1x)]
(1 * 5 + x * 5) = 9[x + -1(3 + -1x)]
(5 + 5x) = 9[x + -1(3 + -1x)]
5 + 5x = 9[x + (3 * -1 + -1x * -1)]
5 + 5x = 9[x + (-3 + 1x)]

Reorder the terms:
5 + 5x = 9[-3 + x + 1x]

Combine like terms: x + 1x = 2x
5 + 5x = 9[-3 + 2x]
5 + 5x = [-3 * 9 + 2x * 9]
5 + 5x = [-27 + 18x]

Solving
5 + 5x = -27 + 18x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-18x' to each side of the equation.
5 + 5x + -18x = -27 + 18x + -18x

Combine like terms: 5x + -18x = -13x
5 + -13x = -27 + 18x + -18x

Combine like terms: 18x + -18x = 0
5 + -13x = -27 + 0
5 + -13x = -27

Add '-5' to each side of the equation.
5 + -5 + -13x = -27 + -5

Combine like terms: 5 + -5 = 0
0 + -13x = -27 + -5
-13x = -27 + -5

Combine like terms: -27 + -5 = -32
-13x = -32

Divide each side by '-13'.
x = 2.461538462

Simplifying
x = 2.461538462

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